AP Chemistry · Handsworth Secondary 2026–27

Unit 2 · Study Guide

Dr. Ras Mulinta
Compound Structure & Properties
Exam-focused review

A one-page map of what the Unit 2 test (and the AP exam) expects. This is a checklist, not a re-teach, if a line doesn't click, go back to that section of the notes package. A periodic table is provided; bond data are given when needed.

Must be able to do

The big idea that ties it together

Structure dictates properties. Electronegativity sets the bond type; the Lewis diagram + VSEPR set the shape; the shape sets the polarity, the hybridization, and the bond order, and those, through F ∝ q₁q₂/r², set what you measure: melting point, conductivity, bond length, bond strength. Draw it right and the macroscopic behaviour falls out.

Don't waste time on (excluded by the CED)

Specific named crystal structures (rock-salt vs. CsCl lattices) · the derivation/depiction of hybrid orbitals · d-orbital hybridization (for 5–6 domains give only the shape) · molecular-orbital diagrams & bonding/antibonding filling · detailed radical (odd-electron) bookkeeping. Know the models and the patterns; skip the orbital math.

Quick self-check (answers in your head, then verify)

  1. Classify the bonding in KBr, F₂, and Al: ionic, covalent, or metallic?
  2. Give the electron geometry, molecular geometry, and bond angle of NH₃.
  3. What is the bond order of each N–O bond in the nitrate ion, NO₃⁻?
  4. Compute the formal charge on the central O in ozone drawn as O=O–O (double bond left, single bond right, one lone pair on the centre).
  5. How many σ and how many π bonds are in hydrogen cyanide, H–C≡N?
  6. Is BF₃ polar or nonpolar? Justify with its shape.
  7. Rank C–C, C=C, and C≡C by bond length (longest first).

Check yourself: 1) KBr ionic (metal + nonmetal), F₂ nonpolar covalent (ΔEN = 0), Al metallic.   2) electron geometry tetrahedral, molecular geometry trigonal pyramidal, angle ≈ 107°.   3) bond order = 4 bonds ÷ 3 bonds = 1.33 (one double shared over three equivalent N–O bonds).   4) FC = 6 − 2 − ½(6) = +1.   5) 2 σ and 2 π (C–H = 1 σ; C≡N = 1 σ + 2 π).   6) nonpolar, trigonal planar with three identical B–F bonds, so the bond dipoles cancel.   7) C–C > C=C > C≡C (higher bond order = shorter bond).

AP Chemistry · Unit 2 Study Guide · Dr. Ras Mulinta · Handsworth Secondary 2026–27 · Pegged to the College Board AP Chemistry CED (topics 2.1–2.7) and BC Chemistry 11 (chemical bonding) / BC Chemistry 12.